0=t+3.75t^2

Solution for 0=t+3.75t^2 equation:

0=t+3.75t^2

We move all terms to the left:

0-(t+3.75t^2)=0

We add all the numbers together, and all the variables

-(t+3.75t^2)=0

We get rid of parentheses

-3.75t^2-t=0

We add all the numbers together, and all the variables

-3.75t^2-1t=0

a = -3.75; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-3.75)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-3.75}=\frac{0}{-7.5}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-3.75}=\frac{2}{-7.5}
=-2/7.5
$